Question

in figure angle acb is right angle and ac= cd and cdef is a parallelogram if angle fec= 10 then calculate angle bde

Answer 1

∆ACD is isosceles therefore angle CAD = CDA

<DCE=10°
therefore <DCA = 80°
therefore <CDA = 50°
<CDE = 80°
now, BDE + EDA = 180°
BDE = 180° - 130°
therefore <BDE = 50°.