Question

in figure ,angle BDC =65, ABC=57, find ACB​

Answer 1

Answer:

Central∠=180∘

∠BAC=90∘

Given ∠ACB=65∘

∠ABC=180∘−∠BAC−∠ACB

∠ABC=180∘−90∘−65∘

∠ABC=25∘

Answer 2

Answer:

an angle of a triangle = 180⁰ degree

Step-by-step explanation:

180 = BDC+abc+acb

180=65+57+acb

180=122+acb

180-122=acb

58=acb

so if u want to check ur ans

u can add all the angles of a triangle

58+57+65= 180

so ur ans is 58⁰.

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thank you.