Question

In figure angle CAB:angle BAD= 1:2 find all the internal angles of Triangle ABC

Answer 1

GIVEN :

∠DAE = 69

∠CBA = x

∠ACB = x + 13

TO FIND :

∠CBA = ?

∠ACB = ?

∠CAB = ?

ASSUMPTION :

⇒ As the angles are in the ratio of 1 : 2 .

Let ∠CAB be y and ∠BAD be 2y .

SOLUTION :

∴ ∠CAB , ∠BAD and ∠DAE lie on same line .

So , we can write that ;

∠CAB + ∠BAD + ∠DAE = 180    

y + 2y + 69 = 180

3y = 180 - 69

y = 111/3

y = 37

∠CAB = 37

∠BAD = 2 × 37 = 74

In Δ ABC :

∠CBA + ∠CAB + ∠ACB = 180   {Angle sum property of a triangle}

x + 37 + x + 13 = 180

2x + 50 = 180

2x = 180 - 50

x = 130 / 2

x = 65

ANSWER :

∠CBA = x = 65

∠ACB = x + 13 = 78

∠CAB = 37

Answer 2

Step-by-step explanation:

fjbhjbbnnnjjhjhhgghbfggh