Question

in figure angle EDC is similar to angle EBA if angle BEC =115°,angle CDE=70°.then find angle DEC,angleDCE,angleEAB,angleAEBand angleEBA

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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

∴    ∠DEC+∠BEC=1800

⇒   ∠DEC+1150=1800

⇒   ∠DEC=1800−1150=650

But, ∠AEB=∠DEC        [Vertically opposite angles]

∴   ∠AEB=650

In △CDE, we have

   ∠CDE+∠DEC+∠DCE=1800

⇒  700+650+∠DCE=1800

⇒  ∠DCE=1800−1350=450

It is given that △EDC∼△EBA

∴  ∠EBA=∠EDC,∠EAB=∠ECD

⇒  ∠EBA=700 and ∠EAB=450

Hence, ∠DEC=650,∠DCE=450,∠EAB=450,∠AEB=650 and ∠EBA=70

Step-by-step explanation:

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