Question

In Figure, AO = OB and ∠ A = ∠ B.
(i) Is ΔAOC≅ΔBOD, Give a reason to support your answer
(ii) Is it true to say that ∠ ACO = ∠BDO?
(iii) Is AC ll BD

Answer 1

Step-by-step explanation:

Here is your answer:

i) In triangle AOC and BOD

angle ACO=BDO (90 degree)

angle AOC=BOD (Vertically opposite angle)

AO=CO (Given)

Therefore, triangle AOC congruent triangle BOD (By AAS)

ii) angle ACO=BDO (C.P.C.T)

iii) AC parallel BD (C.P.C.T)

Hope it's helpful to you !

Answer 2

Answer:

1) In triangle AOC and triangle DOB

angle 1 = angle 2 ( vertically opp. angle )

Angle C = angle D ( each 90 ° )

AO = OB ( GIVEN )

so, triangle AOC congruent triangle DOB ( by criteria A.A.S. )

2) yes , ∠ ACO = ∠BDO ( by C.P.C.T. )

3) AC ll BD ( by C.P.C.T )

HOPE THIS WILL HELPS U....BE HAPPY......