Question

In figure aob is a line and ray oc is perpendicular to ab . If od is another ray lying between ob and oc prove that angle cod =1/2 ( angle aod- angle bod)

Answer 1

Answer:

Ray OC is perpendicular to AB

∴ ∠AOC = ∠BOC = 90° …. (i)

Now, from the figure and eq. (i), we can write

∠AOC = ∠BOC

⇒ ∠AOC = ∠BOD + ∠DOC

⇒ ∠AOD – ∠COD = ∠BOD + ∠DOC

⇒ ∠AOD – ∠BOD = ∠COD + ∠DOC

⇒ ∠AOD – ∠BOD = 2 * (∠COD)

⇒ ∠COD = ½ * [∠AOD – ∠BOD]

Hence Proved

Answer 2

Answer:

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