Question

in figure APB and CQD are semicircles of diameter 7 cm each while ARC and BSD are semicircles of diameter 14 cm each find the perimeter and area of the shaded region

Answer 1

area of APB and CDQ are equal because r=7/2 cm
so area of APB = 1/2πr*r
so 1/2*22/7*7/2*7/2=77/4cm^2
so area of CQD =77/4cm^2
now area of ARC &area of BSD are equal because r=7cm
so,area of ARC = 1/2*22/7 *7*7=77cm^2
so,area of BSD=77cm^2
by sub area of ARC-area of APB= 77-77/4=221/4cm^2
so area of BSD-area of CQD =221/4cm^2
for shades region area =221/4+221/4= 442/4 cm^2

Answer 2

hope it helps pakka answer