in figure BCPQ andBCDA are two parellogram on the same base BC then the value of x+yis
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x+y=20+100
=120 is the answer
=120 is the answer
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in parallelograms opposite angles are equal
=> in paralleolgram ABCD y=> 100 degrees
now angle AQB => 180-120=>60degrees
now in triangle AQB => x=180-(100+60)
=> x=180-160=>20degrees
therefore x+y => 60+20=> 80 degrees
=> in paralleolgram ABCD y=> 100 degrees
now angle AQB => 180-120=>60degrees
now in triangle AQB => x=180-(100+60)
=> x=180-160=>20degrees
therefore x+y => 60+20=> 80 degrees
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