Question

In Figure, BD 1 AC, CE 1 AB such that BD = CE, show that :
(a) ABCE = ACBD (6) BE = CD

the person who answers step by step will be marked as brainlist...
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Answer 1

Step-by-step explanation:

In ∆ ABD and BDC we have,

AD = CD ( mid point of AC).

BD = BD ( common).

ADB = BDC ( each 90°)

so by SAS congruence ∆ABD = ∆BDC

In ∆ACE and ∆BCE

AC = BC ( as isosceles triangle)

CE = CE ( common)

CEB = CEA ( each 90°)

so by SAS ACE = BCE

so we conclude that in this triangle all triangles are equal.