Question

In figure BD and CD are angle bisectors of ∟ABC and ∟ACE respectively. Prove that ∟ BDC= 1/2 ∟BAC. plss solve fast

Answer 1

Answer:

c

Step-by-step explanation:

But ∠DCE = 1 ∠ACE and

2

⇒ 1 ∠DBC = 1 ∠ABC

2 2

Now ∠BDC = ∠DCE - ∠DBC

= 1 (∠ACE - ∠ABC)

2

= 1 (∠ACE + ∠ABC - ∠ACE)

2

∴ ∠BDC = 1 ∠BAC

Answer 2

Answer:

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