In Figure below, show that (i) AB || CD (ii) EF || GH
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Answer:
In the figure ,
∠ABC = 65°
∠BCD = 32° + 33° = 65°
∴ ∠ABC = ∠BCD [Alternate Interior angles ]
∴ AB || CD ................................ (1)
∠ CEF = 148°
∠ DCE = 32°
∠ CEF + ∠ DCE = 180°
148° + 32° = 180° [ Interior angles on the same side of the transversal ]
∴ CD || EF ........................................(2)
From (1) and (2) ,
AB || EF
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Step-by-step explanation:
Answered by
3
Given:
In fig, tree angles are provided.
To show:
(i) AB || CD (ii) EF || GH
Step-by-step explanation:
- In the figure ,Firstly name the intersection part of two lines as P,Q,R,S.
- Now,∠FRD=50°
- Also ∠FRD+∠DRE=180°(L.P.A)
∠DRE=130°
- Thus,∠APF=∠FRD=130°
also∠APF=∠FRD=130°(Alternate angle)
Hence,AB || CD
- Now(ii)
∠GQB = 50°
∠FRD = 50°
Thus∠GQB =∠FRD = 50° (Alternate angle)
Hence,EF || GH
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