Question

in figure , bo and co are bisector of exterior angle at b and c respectively. If angle boc=68 degree, then find angle A

Answer 1

this should be the answer for this question

Answer 2

answer : let the angles be x

x+x+68°=180° (angle sum property of triangle)

2x=180° -68°

2x=112°

x=112°/2

x=56°

now,

56°+56°+ABC = 180°

112°+ABC=180°

ABC=180°-112°

ABC=68° and ACB= 68°

ABC+ACB+A=180°

68°+68°+A=180°

136°+A=180°

A=180°-136°

A= 44°

so,

option (a) is correct (a) 44° (b) 108° (c) 52° (d) none of these