Question

In figure, C and D are points on the semi-circle described on BA as diameter. Given BAD = 80 degree and angle DBC = 40 degree . Calculate angle ABD and angle BDC.​

Answer 1

Answer:

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Step-by-step explanation:

We have ∠ADB=90

o

....... (Angles formed in a semicircle is a right angle)

Again ∠ABD=180

o

−(∠ADB+∠BAD)

=180

o

−90

o

−70

o

=20

o

;

∠ADC=180

o

−∠ABC ........ (opposite angles of a cyclic quadrilateral)

=180

o

−(∠ABD+∠CBD)

=180

o

−50

o

=130

o

∠BDC=∠ADC−∠BDA=130

o

−90

o

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