In figure cd is 150 meter .tan x =3/4 and tan y=5/7.find the length of AB
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In triangle ABC
tan x=AB/BC
3/4=AB/BC
BC = 4AB /3.
In triangle ADB,
tan y =AB /BC+150
5/7= AB/BC+150
7AB= 5BC +750
7AB =5(4AB/3)+750
21AB =20 AB +2250
AB =2250 m........
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