Question

In figure ,CE is parallel to AB , angle ABC = 65° and angle ECD = 60° . Find angle BCE
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Answer 1

Solution: As we can see in the figure.

y + 320 = 180o (Sum of interior angles)

y = 1480

Now,

y and ∠BDE are linear pairs

1480 + ∠BDE = 1800

∠BDE = 320.

∠BED + 1220 =1800 (Linear pair angles)

∠BED = 580

By using angle sum property of a triangle;

∠BDE + ∠BED + x= 1800

320 + 580 + x = 1800

x = 1800 – 900

x = 900

Answer 2

Answer:

The correct answer is 900

Step-by-step explanation:

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