Question

In figure chord AB=18 cm and PQ is perpendicular bisector of chord AB
which meets the chord on point M. If MQ-3cm then find the radius of circle.
​

Answer 1

Answer:

According to the question,

Let OA = x = OP = OB

AB = 2x

OM = x - 3

In△OMP

x2=(9)2+(x−3)2

x2=81+x2+9−6x

90=6x

x=15

∴AB=2×15=30cm.

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