in figure, chord MN and chord RS intersect at point D. if RD=15, DS=4 MD=8 then find DN
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If two chords of a circle intersect each other in the interior of the circle, then the product of the lengths of the two segments of one chord is equal to the product of the lengths of the two segments of the other chord.
MD×DN=RD×DS
⇒8×DN=15×4
⇒DN= 8/60
=7.5 units
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