Math, asked by darshdave, 7 months ago

in figure DE | BC. DE = 3 cm, BC = 9 cm and or (AADE) = 30 cm? Find ar (trap bced) ​

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Answered by Liyutsararename
3

Answer:

area of trapezium BCED = 10/3

Step-by-step explanation:

in tri ADE and tri ABC

angle A = angle A(common angle)

angle ADE = angle ABC(corresponding angles as  DE//BC)

tri ADE ~(similar to) tri ABC (by A.A test)

AD/AB = DE/BC = AE/AC [corresponding sides of the similar triangles are in proportion]

so DE/BC is an corresponding sides

the theorem which will be used here is :

theorem is : the ratio of the areas of polygon is equal to the ratio of the squares of the corresponding sides.

area of trapezium BCED / area of tri ADE = BC^2/DE^2 [by theorem]

[area of trapezium BCED  = area of tri ABC - area of tri ADE]

area of trapezium BCED / area of tri ADE = 3^2/9^2

area of trapezium BCED / area of tri ADE = 9/81

[area of tri ADE = 30cm]

area of trapezium BCED / 30 = 9/81

area of trapezium BCED = 9*30/81 => 30/9 = 10/3

area of trapezium BCED = 10/3

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