Question

in figure, DE//BC , find EC​

Answer 1

Answer:

Let,EC = x ,AE =9-x

By Thalus theorem,

AD/AB =AE/AC

=>2/6=9-x/9

=>1/3 =9-x/9

=>9-x=9/3 [ by cross multiplication]

=>9-x =3

=> -x =3 -9

=> x=6.

Therefore, EC =6.

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