Question

In figure DE|| BC. If BD = x-3, AB=2x, CE= x-2 and AC = 2x+3. Find the value of x
А​

Answer 1

Answer:by Thales theorem,

AB/BD=AC/CE

2x/x-3 = 2x+3/x-2

2x(x-2) = 2x+3(x-3)

2x²-4x = 2x²-6x+3x-9

-4x = -3x-9

-4x+3x = -9

-x = -9

x=9

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