Question

in figure de || bc . if bd = x-3 and ab = 2x ce =x-2 and ac =2x+3. Find x

Answer 1

In triangle ABC, DE || BC.  Then x = 9

Step-by-step explanation:

The question is incomplete. The figure is missing.

Given: In triangle ABC, DE || BC.

BD = x-3

AB = 2x

CE = x-2

AC = 2x+3

Find: X.

Solution:

Since DE is parallel to BC, according to the basic proportionality theorem, we get:

(AB / DB) = (AC / EC)  

(2x / x-3)=(2x+3 / x-2)

 2x (x-2) = (2x+3) (x-3)

2x^2 - 4x = 2x^2 +3x -6x -9

 x - 9 = 0

Therefore x = 9

Answer 2

Step-by-step explanation:

your answer is here with step by step