Question

in figure de is parallel to qr and ap and bp are the bisectors of angle eab and angle rba respectively find angle apb

Answer 1

Answer:

See diagram enclosed

let angle eap = angle bap = x (ap bisector)

let angle rbp = angle pba = y bp is bisector

angle eab + angle abr = 180 degrees as ae and br are parallel

2 * x + 2 * y = 180 deg x + y = 90

angle apb = 180 - x - y in trianle apb

angle apb = 180 - 90 = 90 deg

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