In figure, EF||DC, FG||CB and GH||BA. Prove that HE||AD
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Answer:
In triangle AOB
GH ll BA
by basic proportional theorem
OH/HA=OG/GB. 1eq.
In triangle OBC
FG ll CB
by basic proportional theorem
OG/GB=OF/FC. 2eq.
In triangle ODC
OE/ED=OF/FC. 3eq.
from 1,2and3 eq.
OH/HA=OG/GB=OF/FC=OE/ED
so OH/HA=OE/ED
by reverse of basic proportional theorem
HE llAD
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