In figure find the value of ∠A + ∠B + ∠C + ∠D + ∠E + ∠F
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72
Answer:
In figure find the value of ∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360°
Explanation:
We know that the sum of all the angles in triangle ACE is 180°
∠A+∠C+∠E=180° ..(1)
We know that the sum of all the angles in triangle BDF is 180°
∠B+∠D+∠F=180°.(2)
Now by adding both equations (1) and (2) we get
∠A+∠C+∠E+∠B+∠D+∠F=180° +180°
On further calculation
∠A+∠B+∠C+∠D+∠E+∠F=360°
Therefore, it is proved that ∠A+∠B+∠C+∠D+∠E+∠F=360°
I hope it will be helpful..☃️
Anonymous:
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Answered by
15
Answer:
∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360°.
Explanation:
In the above figure we see that :-
Triangle ABC = 180° (Angle sum property of a triangle) Also,
Triangle DEF = 180° (Angle sum property of a triangle)
So, Triangle ABC + Triangle DEF = 180° + 180°
= 360°
Therefore, ∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360°.
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