In figure from a point A which is in the exterior of the circle. The points of contact of the tangents are P and Q as shown in the figure. A line I touches the circle at R and intersects AP and AQ in B and C respectively. If AB c, BC = a, CA = b, then prove that two tangents are drawn to a circle (1) AP + AQ = a + b +c (2) AB + BR = AC + CR AP AQ = 4t0*C
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Answer:
140degree
Step-by-step explanation:
Tangent is perpendicular to radius at point of contact.
So, ∠ABO=∠ACO=90∘
In a quadrilateral, the sum of the angles is 360∘.
∠BAC+∠BOC+∠ABO+∠ACO=360∘
∴∠BAC+∠BOC=180∘
∠BOC=180∘−40∘
∠BOC=140∘
Hope This will helps you
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