Question

In figure given below , AB parellel to DC ,BC = AD = 13cm , AB = 22 cm and DC = 12 cm calculate the height of the trapezium ABCD .

Answer 1

Answer:

$221cm^{2}$

Step-by-step explanation:

Area of trapezium  =  1/2(Sum of parallel sides * the distance between them)

                               =  1/2[(12+22)*13]

                               =  1/2(34*13) = 17 * 13

                                      =  $221cm^{2}$

MARK AS BRAINLIEST