Question

in figure given below AN=AC, ANGLE BAC=52 ANGLE ACK =84 and BCK is a St. line. prove that NB=NC.

Answer 1

given: an=ac
ang.bac=52°
ang.ack=84°

by exterior angle theorem,
ack=bac+abc
84=52+abc
abc=84-52
=32

ang.acn=(180-52)/2
=128/2
=64

hence
Ang.ncb=180-(64+84)
=180-148
=32

hence
ang.ncb =ang.abc
thus NB=nc

Answer 2

Answer:

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