in figure given below AN=AC, ANGLE BAC=52 ANGLE ACK =84 and BCK is a St. line. prove that NB=NC.
Attachments:
Answers
Answered by
65
given: an=ac
ang.bac=52°
ang.ack=84°
by exterior angle theorem,
ack=bac+abc
84=52+abc
abc=84-52
=32
ang.acn=(180-52)/2
=128/2
=64
hence
Ang.ncb=180-(64+84)
=180-148
=32
hence
ang.ncb =ang.abc
thus NB=nc
ang.bac=52°
ang.ack=84°
by exterior angle theorem,
ack=bac+abc
84=52+abc
abc=84-52
=32
ang.acn=(180-52)/2
=128/2
=64
hence
Ang.ncb=180-(64+84)
=180-148
=32
hence
ang.ncb =ang.abc
thus NB=nc
Answered by
15
Answer:
Hope that it will hep you please mark theis answre as brainlist
Attachments:
Similar questions