Question

In figure given below, area of triangle ABR is equal to the area of
parallelogram ABCD. If altitude QR is 18 cm long, what is the area
of triangle DAP, where P is the midpoint of DC?​

Answer 1

Answer:

I think this shall do it, it might be a little different from values. but method of same.

Step-by-step explanation:

We know that, area of a triangle =

× b × h

and area of a parallelogram = b × h (corresponding height)

Given, Area of ∆AFB = Area of parallelogram ABCD

× AB × EF = DC × h

× 10 × 16 = 10 × h

10h = 80

h = 8 m

O is the mid point of DC, hence DO =

× DC =

× 10 = 5 m

Area of ∆DAO =

× DO × h =

× 5 × 8 = 20 m^2

Answer 2

Answer:

Broo too difficult

Step-by-step explanation: