in figure given below bc =5cm angle b=90 degree ab =5ae CD =2ae and Ac =Ed calculate the sides
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HEYA!
SOLUTION
In triangle ABC
(5x)² + (5)² = AC²
25² + 25 = AC²
In triangle EDB
(5cm + 2x)² + (4x)² = ED²
25 + 20x + 4x² + 16² = ED²
as ED = AC
25 + 20X + 20X² = 25X² + 25
5(4X² + 4X) = 25X²
X(4X + 4) = 5X²
4 = 5X - 4X
So 4 = 5X - 4X
So x = 4
AE = 4 cm
CD = 2x4 = 8 cm
AB = 2x5 cm = 20 cm
AC² = 20² + 5²
AC = √400 + 25
= √425
= 5√17
HOPE THIS HELPS
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Answered by
9
In triangle ABC
(5x)² + (5)² = AC²
25² + 25 = AC²
In triangle EDB
(5cm + 2x)² + (4x)² = ED²
25 + 20x + 4x² + 16² = ED²
as ED = AC
25 + 20X + 20X² = 25X² + 25
5(4X² + 4X) = 25X²
X(4X + 4) = 5X²
4 = 5X - 4X
So 4 = 5X - 4X
So x = 4
AE = 4 cm
CD = 2x4 = 8 cm
AB = 2x5 cm = 20 cm
AC² = 20² + 5²
AC = √400 + 25
= √425
= 5√17
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