Question

in figure given below , DEllBC and BDllCE . Prove that ABC is an isosceles triangle.
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Answer 1

can u mention the sum properly.

Answer 2

Step-by-step explanation:

From the question it is given that,

DE∥BC and BD=CE

So, we have to prove that ABC is an isosceles triangle.

Consider the triangle ABC,

AD/DB=AE/EC

Given, DB=EC … [equation (i)]

Then, AD=AE … [equation (ii)]

By adding equation (i) and equation (ii) we get,

AD+DB=AE+EC

So, AB=AC

Therefore, △ABC is an isosceles triangle.

I hope it helps you