Math, asked by santoor1, 1 year ago

In figure given below L parallel to m bisectors of angle RQB and angle DRQ intersects at p Find the measure of angle RPQ

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Answers

Answered by omkar2709
44
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hardil: why angle DRQ+ angle BPQ = 180
Answered by throwdolbeau
21

Answer:

∠RPQ = 90

Step-by-step explanation:

∠DRQ and ∠RQB form pair of adjacent angles

⇒ ∠DRQ + ∠RQB = 180

Since, PQ and PR are angle bisectors

⇒ 2x + 2∠RQP = 180

⇒ x + ∠RQP = 90

⇒ ∠RQP = 90 - x

Now , in ΔRPQ by using angle sum property of a triangle

∠RQP + ∠RPQ + ∠PRQ = 180

⇒ 90 - x + ∠RPQ + x = 180

⇒ ∠RPQ = 90

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