Question

In figure given here , if AB||CD,angleAPQ= 50° and angle PRD=127°, find x and y.​

Answer 1

Answer:

PRD+PRQ=180(LINEAR PAIR)

PRQ=180-127=53

RPB+PRD=180(ADJACENT ANGLE)

RPB=180-127=53

APQ+QPR+RPB=180(STRAIGHT ANGLE)

180-APQ+RPB=QPR

180-50+53=77=QPR

X=77

PRQ+X+Y=180

180-53+77=Y

Y=50

Answer 2

Answer:

x=77 degree

y=50 degree

Step-by-step explanation:

since PRD+PRQ=180(linear pair)

so PRQ=180-127=53

now RPB+PRD=180(it is an adjacent angle)

then RPB=180-127=53

as we know that APQ+QPR+RPB=180(striaght angle)

 therefore 180-APQ+RPB=QPR

180-50+53

QPR=77 degree

angle x=77  degree

PRQ+x+y=180  degree

180-53+77=y

angle y=50  degree

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