Question

in figure if ab||CD and CD||EF FIND angle ACE

Answer 1

Answer:

$\angle ACE = 20^o$

Step-by-step explanation:

$\red{\underbrace{Question:-}}$

In figure if ab||CD and CD||EF FIND angle ACE?

$\red{\underbrace{Solution:-}$

As per the diagram, lines CD∣∣EF and CE is transveral.

We know that sum of interior angles is equal to 180 degrees

$\angle ECD + \angle CEF = 180^o$

$\angle ECD +130^o = 180^o$

$\angle ECD = 180^o -130^o$

$\angle ECD = 50^o$

$\Rightarrow\boxed{\red {\angle ECD=50^o}}$

$\bigstar$ As per the diagram, lines AB∣∣CD and CA is transveral. $\bigstar$

We know that alternate angles are equal.

$\angle BAC = \angle ACD$

$\angle BAC = \angle ACE +\angle ECD$

$\angle 70^o = \angle ACE +50^o$

$20^o =\angle ACE$

∴ $\angle ACE = 20^o$

$\Rightarrow\boxed{\red {\angle ACE=20^o}}$

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