in figure if ab||CD, Δapq=50° and Δprd=127° then find x and y
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where is ur figure?
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Hello mate ☺
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Solution:
AB∥CD, ∠APQ=50° and ∠PRD=127° (Given)
∠x=50°=∠APQ (Alternate Interior Angles)
∠APR=∠PRD (Alternate Interior angles)
⇒50°+∠y=127°
⇒∠y=127°−50°=77°
Therefore, ∠x=50° and ∠y=77°
I hope, this will help you.☺
Thank you______❤
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