Question

In figure, if AB ∥ CD , ∠APQ = 500° and ∠PRD = 1270°
, find x and y.​

Answer 1

Answer:

Given,

AB || CD, ∠APQ = 500° and ∠PRD = 1270°

Find,

the value of x and y.

Step-by-step explanation:

SO,

=> ∠PQR=∠APQ (Alternate angle)

=> x=50°

=> ∠PRQ+∠PRD=180°

=> ∠PRQ+127° =180°

=> ∠PRQ=180° −127° =53°

=> ∠PQR+∠QPR+∠PRQ=180°

(Angle sum property of trianlge

=> x+y+53° =180°

=> 50° +y+53° =180°

=> y=180° −103° =77°

Hence,

x value is 50° and y value is 77°

Answer 2

Step-by-step explanation:

Using Trigonometric identities: Sin2x = 1- Cos2x

Sin2x = 1 – (4/5)2

= 1 – 16/25

= (25 – 16) / 25

= 9/25

Sin x = 9/25−−−−√

= 3/5