In figure, if AB ║ CD, CD ║ EF, AE ⊥ EF and θ = 140 , then
find values of x,y,z and w.
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In figure, if AB ║ CD, CD ║ EF, AE ⊥ EF and θ = 140 , then values of x = 125 ,y = 125,z = 35
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SINCE,DC//EF , and Angle FED=140°...then
Angle FED = Angle FCD =140°...(Opposite interior angles)
angle CFE =40°...(Sum of co-interior angles =180°)
angle CFE = angle EDC = 40°...(Opposite interior angles)
Since,AB//DC...then
ANGLE EDC + ANGLE ADC = 180°
40° + ANGLE ADC =180°...(straight lines)
ANGLE ADC= 140°
ANGLE ADC = ANGLE ABC = 140°...(Opposite interior angles)
ANGLE FCD + ANGLE BCD = 180°...(straight lines)
140° + ANGLE BCD = 180°
ANGLE BCD = 40°
ANGLE BCD = ANGLE BAD = 40°...(Opposite interior angles)
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