Math, asked by pravin342, 11 months ago

in figure,if AB=CD,prove that AC=BD.

Answers

Answered by nidhi2111

5

Answer:

. A______. B_____. C_________. D

AC =BD (GIVEN) - (1)

AC=AB+BC(point B lies between A & C)-(2)

BD=BC+CD(Point C lies between B & D)-(3)

From (1),(2),(3) we get

AB+BC=BC+CD

AB+CD=HENCE PROVED

Previous Question

Next Question

Similar questions

English, 5 months ago

PICK THE ODD ONE OUT. (PROFESSIONS) Doctor Father Teacher Carpenter...

Hindi, 5 months ago

5 अधोलिखितान् समयवाचकान् अङ्कान् पदेषु लिखित 1)2:30 2)7:00 3)3:30 1. 4)5:00...

Science, 5 months ago

Write the SI unit of the given physical quantity...

Geography, 11 months ago

write 100 species animals and fish...

English, 11 months ago

What is the singular of shelf...

Math, 1 year ago

A wooden box (open at the top) of thickness 0.5 cm, length 21 cm, width 11 cm and height 6 cm is painted on the inside. The expenses of painting are Rs. 70. What is the rate of painting per square centimetres? a. Re 0.7 b. Re 0.5 c. Re 0.1 d. Re 0.2...

Math, 1 year ago

For the product n(n + 1)(2n + 1), n ∈ N, which one of the following is not necessarily true? a. It is even b. Divisible by 3 c. Divisible by the sum of the square of first n natural numbers d. Never divisible by 237...

Math, 1 year ago

ABCD is a rhombus with the diagonals AC and BD intersecting at the origin on the x-y plane. The equation of the straight line AD is x + y = 1. What is the equation of BC? a. x + y = –1 b. x – y = –1 c. x + y = 1 d. None of these...