Question

in figure, if AB||DC, find the value of x.
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Answer 1

Step-by-step explanation:

ABCD is a trapezium and AB//CD so,

∆DOC ~ ∆BOA

hence,

DO/OB= OC/OA

(x-2)/(x-1)=(x+3)(x+5)

on coponendo dividendo

(x-2+x-1)/{x-2-(x-1)}=(x+3+x+5)/{x+3-(x+5)

(2x-3)/(x-2-x+1)=(2x+8)/(x+3-x-5)

(2x-3)/-1= (2x+8)/-2

-2(2x-3)= -1(2x+8)

2(2x-3)= 1(2x+8)

4x-6=2x+8

4x-2x= 8+6

2x= 14

x=7

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