Math, asked by sheelachannakeshava, 9 months ago

In figure if AB parallel DC and AC, PQ intersect each other at the point O. prove that OA×CQ=OC×AP

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Answers

Answered by bharat9291
70

Step-by-step explanation:

in triangle APO and triangle CQO

angle PAO = angle OCQ ( alternate angle)

angle POA = angle COQ( vertical opposite angle )

by AA criteria triangle APO is similar to triangle CQO

so

(AP/ CQ )= ( AO/ CO)

cross multiplication

AP X OC = CQ X OA

Answered by Krish1735
2

Answer:

Step-by-step explanation:

In triangle APO and triangle CQO

angle PAO = angle OCQ ( alternate angle)

angle POA = angle COQ( vertical opposite angle )

by AA criteria triangle APO is similar to triangle CQO

so

(AP/ CQ )= ( AO/ CO)

cross multiplication

AP X OC = CQ X OA

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