Question

In figure if AD is bisector of angle A, show that:i]AB>BD ii]AC >VS​

Answer 1

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if AD is bisector then

if AD is bisector thenangle(BAD) =angle(CAD)

if AD is bisector thenangle(BAD) =angle(CAD) so

if AD is bisector thenangle(BAD) =angle(CAD) soAD is common in ABD and ACD

if AD is bisector thenangle(BAD) =angle(CAD) soAD is common in ABD and ACDso

if AD is bisector thenangle(BAD) =angle(CAD) soAD is common in ABD and ACDsouse triangle property

if AD is bisector thenangle(BAD) =angle(CAD) soAD is common in ABD and ACDsouse triangle propertywe can easily prove

if AD is bisector thenangle(BAD) =angle(CAD) soAD is common in ABD and ACDsouse triangle propertywe can easily proveAB>BD

if AD is bisector thenangle(BAD) =angle(CAD) soAD is common in ABD and ACDsouse triangle propertywe can easily proveAB>BDand

if AD is bisector thenangle(BAD) =angle(CAD) soAD is common in ABD and ACDsouse triangle propertywe can easily proveAB>BDandAc>CD