In figure, if angle cab = angle CED then prove that
AB×DC = ED×BC.
Attachments:
Answers
Answered by
45
Step-by-step explanation:
In ∆ CAB and ∆ CED
angle CAB = angle CED ( given)
angle C = angle C ( common)
therefore ∆ CAB ~ ∆ CED
AB/ED = BC / DC
cross multiply
AB × DC = ED × BC
Answered by
2
Step-by-step explanation:
hope you can view that I've explained with diagram
Attachments:
Similar questions