Question

In figure, if angle cab = angle CED then prove that
AB×DC = ED×BC.​

Answer 1

Step-by-step explanation:

In ∆ CAB and ∆ CED

angle CAB = angle CED ( given)

angle C = angle C ( common)

therefore ∆ CAB ~ ∆ CED

AB/ED = BC / DC

cross multiply

AB × DC = ED × BC

Answer 2

Step-by-step explanation:

hope you can view that I've explained with diagram