Question

In figure, if angle DBC = 70° and angle BAC = 40°, find angle BCD.​

Answer 1

Answer:

GIVEN angle DBC = 70°

angle BAC = 40°

angle BCD = ?

Now, angle BAC= angle BDC = 40°

IN triangle BDC,

Angle DBC + Angle BDC+ Angle BCD= 180°

70° + 40° + angle BCD = 180°

Angle BCD= 180 ° -110° = 70°

Answer 2

Answer:

Angel DBC +BAC+BCD=180

Then 70+40+x=180

110+x=180

x=180-110=70

so angle bcd=70

hope it's helpful for you .

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