Question

in figure if AOB is a diameter of circle and AC=BC then angle CAB =
​

Answer 1

Step-by-step explanation:

The value of CAB = 45°.

Step-by-step explanation:

We are given in the figure that AOB is diameter and sides AC = BC.

In the figure, as we know that the angle subtended at the circumference of the circle by the diameter of the circle is of right angle, that means;

ACB = 90°        {right angle}

Since the sides AC and BC are equal, this means that;

CAB = CBA --- (1)  {because the equal sides have equal opposite angles}

Now, considering the triangle ABC;

ACB + CAB + CBA = 180°   {angle sum property of the triangle}

90° + CAB + CAB = 180°     {using condition 1}

90° + 2CAB = 180°

2CAB = 180° - 90°

2CAB = 90°

CAB =  = 45°

Answer 2

Answer:

We know that the angle at circumference subtended by the diameter of the circle is right angle.

Thus ∠ACB=90

In △ABC

 AC=BC (given)

=>∠CAB=∠CBA

Now,

 ∠CAB+∠CBA+∠ACB=180  

 

=>∠CAB+∠CAB=180−90

=>∠CAB=  90/2

=>∠CAB=45  

agar acha laga to thank our brainliest banab doh sharma hoh maat

Step-by-step explanation: