in figure if aob is a line, op bisects angle BOC and op bisects angle AOC show that angle poq is a right angle? please answer it's urgent
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angle cop = pob, as op bisects boc
let angle cop be x so, angle pob is also x
angle Aoq = Qoc,as op bisects Aoc
let anglr Aoq be y, so Qoc is also y
Angle PoQ is x+y
.....
x+x+y+y =180 (angles on a straight line )
2(x+y)=180
x+y =180/2
x+y=90
angle poq =90
hence proved
let angle cop be x so, angle pob is also x
angle Aoq = Qoc,as op bisects Aoc
let anglr Aoq be y, so Qoc is also y
Angle PoQ is x+y
.....
x+x+y+y =180 (angles on a straight line )
2(x+y)=180
x+y =180/2
x+y=90
angle poq =90
hence proved
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