In figure, if D is mid point of BC, the value of tan x°/ tan y° is = (a) 1/3 (b) 1 (c) 2 (d) 1/2
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Answer:
n △ACD
tanx
∘
=
CD
AC
In △ABC
tany
∘
=
CB
AC
Now D is midpoint of CB
∴CB=2CD
Dividing (i) by (ii)
⇒
tany
∘
tanx
∘
=
CB
AC
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