in figure if PQ is perpendicular to SR, PQ parallel to sr, D Angel SQR is equal to 28° and Angle QRT = 65° then find the values of X and Y
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Hello mate ☺
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Solution-
It is given that PQ∥SR. Therefore, ∠QRT=∠PQR (Alternate Interior Angles)
⇒65°=x+28°
⇒x=65°−28°=37°
In ∆PQS, we have
x+y+∠SPQ=180° (Sum of three angles of a triangle =180°)
⇒37°+y+90°=180° ( It is given that ∠SPQ=90°)
⇒y=180°-37°−90°=53°
Therefore, x=37° and y=53°
I hope, this will help you.☺
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