In figure, if PQ ll PS , PQ II SR angle SQR = 28º and
QRT = 650 degree then find the values of x and y
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Answer:
. x = 37°
. y = 53°
Step-by-step explanation:
GIVEN PQ II SR
⇒∠QRT = ∠PQR ( Alternate angles )
⇒ 65° = x + 28°
⇒ x = 65° - 28°
⇒ x = 37°
In ΔPQS, x + y + ∠QPS = 180°( Angle Sum Property)
⇒ 37° + y + 90°= 180°
⇒y = 180° - ( 90°+ 37°)
⇒y = 180° - 127°
⇒y = 53°
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Check the other answer: )
Step-by-step explanation:
The other person has answered your question pretty well, So I think there is no need to explain it again.
Please mark her answer as the Brainliest ,she deserves it.
Hope you will consider my request.
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