Question

In figure, if PQ ll RS and angle PXM=50° and MYS= 120°, find the value of x
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Answer 1

Answer:

Draw a line through M parallel to PQ and RS

angle A= 50 degree( alternate angle)

angle C+120degree(linear pair)

also angle b=angle c( alternate angle)

b=60 degree

x-20 degree+angle b+angle a =360 degree

x-20+60 +50=360degree

x=360-110+20

X=270 degree

MAY IT HELP YOU Jai Shri Ram

Answer 2

The value of x = 270°

Given:

In figure, PQ || RS and the angle PXM = 50° and MYS = 120°

To find:

The value of x

Solution:

If we draw a line AB through M parallel which is parallel to PQ and RS

⇒ Angle ∠BMX = 50° ( alternate angle to ∠PMX )

Since RYS is linear angle

⇒ ∠RYM = 180° - ∠SYM

⇒ ∠RYM = 180° - 120° = 60°

Here ∠RYM will be alternative angle to ∠BMY

⇒ ∠BMY =  60°  

From above data ∠XMY =  ∠BMX +∠BMY

= 50° + 60° = 110°    

As we know at point A the angle will be equal to 360°

then   (x-20)° + ∠XMY = 360°

⇒ x - 20° + 110° = 360°

⇒ x - 90° = 360°

⇒ x = 270°

The value of x = 270°

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