Question

in figure if PQR is the tangent to a circle at Q whoes centre is O. AB is a chord parallel to pR and triangle BQR = 70 angle AQB is ​

Answer 1

Answer:

Step-by-step explanation:

As OQ⊥ PR

(radius ⊥ tangent) & AB∣∣PR

⇒AB⊥OL

and perpendicular from centre to chord bisects the chord.

⇒AL=BL,

∠QLB=∠QLA

& LQ=LQ\Rightarro$$ By SAS

congruency, ΔQLA≅ΔQLB

⇒∠AQL=∠BQL=20  

o

 (90  

o

−70  

o

)

⇒∠AQB=40  

o

.