in figure if pr= PS, pt = pq ,angle pts=angle pqr =90 degree , prove that rq=st and rt=sq.
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Step-by-step explanation: In triangle RTS and RQS
angle RTS = angle RQS {linear pair}
RS=RS {common}
angle R = angle S {PR=PS}
therefore, RTS ≅ RQS {ASA}
cpct- TS=RQ
In ΔTRO and ΔQSO
∠rto =∠sqo =90
rq =st {proved}
∠rot = ∠sot {VOA}
∴ΔTRO ≅ ΔQSO {ASA}
CPCT- rt = qs
debojyoti94:
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